25x^2-60x-54=0

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Solution for 25x^2-60x-54=0 equation:



25x^2-60x-54=0
a = 25; b = -60; c = -54;
Δ = b2-4ac
Δ = -602-4·25·(-54)
Δ = 9000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9000}=\sqrt{900*10}=\sqrt{900}*\sqrt{10}=30\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30\sqrt{10}}{2*25}=\frac{60-30\sqrt{10}}{50} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30\sqrt{10}}{2*25}=\frac{60+30\sqrt{10}}{50} $

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